How many moles of glucose (c6h12o6) are in 4.0 liters of a 4.5 m c6h12o6 solution?

How many moles of glucose (c6h12o6) are there in 4.0 liters of a 4.5 ml solution of c6h12o6?

Molarity is the ratio of moles of solute to the volume of the solution in liters. In this case we have 4.5 M or 4.5 mol/L which, multiplied by 4 liters of solution, the moles of glucose contained in the solution are equal to 18.0 mol of glucose.

18 moles Explanation: The molarity of a solution is defined as the number of moles of dissolved solute per liter of solution.
Where,
n= moles of solute = ? = volume of solution in L = 4.0 L Putting the given values: Thus, 18 moles of glucose are present in 4.0 L of 4.5 M glucose solution.

That would be 4.5/4.0 = 1.1, so your answer is D or Number 4, which is 1.1!

number of moles (mol) = molar concentration (mol/L) x volume (L) Hope this helps! Have a nice day!

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