How Many Electrons In An Atom Can Have Each Of The Following Quantum Number Or Sublevel Designations?

a) Six electrons b) Two electrons c) Fourteen electrons Explanation: n is the principal quantum number and defines the energy level of the orbit. The shape of the orbit is described by the azimuthal quantum number (l) and also determines the angular momentum. Their values ​​give the following information l = 0, define the s orbital (one orbital) l = 1, define the p orbitals (three orbitals) l = 2, define the d orbitals (five orbitals) l = 3, define the f orbitals (seven orbitals) These are specified by the magnetic quantum number (ml) which gives the orientation of the orbital. Its value varies from +1 to -1, for example, the ml value of five d orbitals is +2, +1, 0, -1, -2. From this information we can predict the number of electrons that will have the given subshell designations a) n = 4 and the orbital is p there are three p orbitals because ml is undefined so six electrons will have this quantum number b) In this part, the orbital is defined, ie ml = +1. A single orbital can only have two electrons, so these electrons will have the given quantum number. c) l = 3, is for the f orbital, which has seven orbitals. The total number of electrons it contains is fourteen. All these electrons will have this quantum number.

b)2 Explanation: Two electrons in an atom can have this quantum number n = 4, l = 0, ml = 0, ms = +1/2. n = principal quantum number representing the principal energy at which the orbit is located. l = azimuthal quantum number gives the shape of the orbitals. ml= is the degeneracy number ms = is the magnetic spin. The orbital designation of this atom is simply 4s. The 4s orbital can only accommodate two electrons. The maximum number of electrons in subshell orbitals is: two electrons for s subshell with one orbital six electrons for p subshell with three orbitals ten electrons for d subshell with five fourteen orbitals electrons for the f subshell with seven orbitals. Learn more: Orbitals #learnwithBrainly

The answer to the following question is explained. Therefore, the number of electrons present with the values ​​n = 5, l = 2, m = -2, s = +1/2 is one (1). Explanation: Here; n represents the principal quantum number l represents the azimuthal quantum number m represents the magnetic quantum number s represents the spin quantum number n = 5, l = 2, m = -2, s = +1/2 Here implies the orbit 5d. In the 5d orbit, 10 electrons. Since the magnetic quantum number is -2, it can have 1 electron. Therefore, the number of electrons present with the values ​​n=5, l=2, m=-2, s=+1/2 is one (1)

the correct answer is 10

It would be 18 electrons I think

Answer 6

Pauli’s exclusion principle says that two electrons cannot have the same set of quantum numbers; that is, two electrons cannot be in the same state. This exclusion limits the number of electrons in the atomic shells and subshells. Each value of n corresponds to a shell and each value of l corresponds to a subshell.

Answer 7

There are 5 elections

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