What is the strength of the magnetic field that will levitate the 2.0 g wire in the figure (Figure 1)? Suppose J = 1.5 A and d = 11 cm. What is the direction of the magnetic field?
Answer
mg = identifier B
===> B = mg/id = 2e-3*9.8/1.5/0.11 = 0.119 T
meaning: off page
F=i(lxB) we obtain the direction of the magnetic field outside the plane of the paper (k).
substituting the values we get B as 0.119 T