What is the mass of the formula gram of case4.2h2o?
So Ca = 40 g/mol S = 32 g/mol O = 16/mol H = 1 g/mol molar mass of CaSO4.2H2O = [(40) + (32) + (16 × 4) + (2 × 1 × 2) + (2 × 16)] = 172 g/mole
Answer: The gram mass formula is 172 g/mol Explanation: As we know, Molar mass of calcium (Ca) = 40 g/mol Molar mass of sulfur (S) = 32 g/mol Molar mass of oxygen (O ) = 16 g/mol Molar mass of hydrogen (H) = 1 g/mol We now need to calculate the mass from the gram formula of In , there is 1 atom of calcium, 1 atom of sulfur , 6 oxygen atoms and 4 hydrogen atoms. The formula gram mass of = Therefore, the formula gram mass of is, 172 g/mol
a. The mass of formula gram of CaSO4.2H2O is equal to 172 grams/mol b. The mass percentage of H2O in CaSO4.2H2O is 20.9% c. The molecular formula of naphthalene is C10H8 d. The total number of moles in 80.0 grams of C2H5Cl is 1.24 moles e. 4.76 moles of Na3PO4 contain 780.64 grams of Na3PO4 Explanation: RMM = relative molecular mass. To calculate the mass of the gram formula of CaSO4.2H2O, you need to add the atomic mass of the individual elements that make up the compound. Here are the atomic masses of the individual elements present in the plaster; Ca=40, S=32, 0=16, H=1. CaSO4.2H2O = 40+32+(16×4)+2((1×2)+16) = 172 grams/mol b. Mass % of H2O in gypsum = (RMM of 2H2O/RMM of gypsum) x 100 RMM of 2H2O = 2((1×2)+16)=36 grams/mol RMM of CaSO4.2H2O (gypsum) = 172 grams /% molar mass of H2O in the plaster = (36/172) x 100 = 20.9% H2O c. The empirical formula of a compound only shows the simplest ratio of atoms in a given compound, not the actual number of atoms. The actual number of atoms in a compound is shown in its molecular formula, which can be used to calculate the compound’s RMM. A specific number (n) multiplied by the number of atoms in an empirical formula gives the molecular formula. (C=12, H=1) (Empirical formula)n = Molecular formula (Total sum of the atomic masses of the elements in the empirical formula)n = Total sum of the atomic masses of the elements in the RMM molecular formula of naphthalene = 128 grams/ mol ( (12×5)+(1×4))n = 64n 64n = 128 n = 128/64 = 2 So (C5H4)2 = C(5×2)H(4×2) = C10H8 d. Number of moles of C2H5Cl = mass of C2H5Cl/RMM of C2H5Cl Say number of moles of C2H5Cl = y Mass of C2H5Cl = 80.0 grams RMM or mass of formula gram of C2H5Cl = 64.5 grams/mol y = 80.0/ 64.5 = 1.24 moles e.g. Number of moles of Na3PO4 = mass of Na3PO4/RMM of Na3PO4 Number of moles of Na3PO4 = 4.76 moles of formula-gram mass of Na3PO4 = 164 grams/mole mass of Na3PO4 = x 4.76 = x/164 x = 4 .76 x 164 = 780.64 grams
The answer to your question is 172 g/mol Explanation: Data CaSO₄ 2H₂O Gram formula mass = ? Process 1.- Determine the number of elements in the compound Calcium 1 Sulfur 1 Hydrogen 4 Oxygen 6 2.- Multiply the number of atoms by their atomic weight Calcium 1 x 40 = 40 Sulfur 1 x 32 = 32 Hydrogen 4 x 1 = 4 Oxygen 6 x 16 = 96 3.- Add the result Formula gram mass = 40 + 32 + 4 + 96 = 172 g/mol
Your answer would be 172.1703 g/ml
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