Use the mesh-current method to find the power dissipated in the 15 ω resistor in the circuit.

Image for Consider the circuit shown in Figure 1. Assume Vs = 55 V. Use the mesh current method to find the power Use the mesh current method to find the power dissipated through the 15 ohm resistor in the circuit.

Consider the circuit shown in Figure 1. Assume Vs = 55 V. Use the mesh current method to find the power dissipated through the 15 ohm resistor in the circuit.

Answer


9.2 (o几 1G几 2ラヲラ 2-13ららー

9.2 (o几 1G几 2ラヲラ 2-13ららー


for the given circuit, find the power dissipated by the 15 ohm resistor.

now we apply KVL on mesh 1.

10I_{1}+5(I_{1}+I_{2}) =V_{s}

now we apply KVL to mesh 2.

23I_{2}+5(I_{1}+I_{2}) =3V_{x}

and Vx is given as the voltage drop across the 4 ohm resistor.

V_{x}=4I_{1}

substituting the above value of Vx into KVL of mesh 2, we get

23I_{2}+5(I_{1}+I_{2}) =3V_{x}

=>23I_{2}+5(I_{1}+I_{2}) =12I_{1}” source=”wp-content/uploads/2021/10/61a2dc409f4b.octet” aria-descriptionpar=”BBC” title=”61a2dc409f4b”/></p>
<p style==>28I_{2} =7I_{1}” source=”wp-content/uploads/2021/10/3cc0dec3b1da.octet” aria-descriptionpar=”bbd” title=”3cc0dec3b1da”/></p>
<p style= =>4I_{2} =I_{1}” source=”wp-content/uploads/2021/10/3b1e87690120.octet” aria-descriptionpar=”baby” title=”3b1e87690120″/></p>
<p style=we substitute the above value of I1 into the mesh equation 1.

10I_{1}+5(I_{1}+I_{2}) =V_{s}

=>40I_{2}+5(5I_{2}) =V_{s}” source=”wp-content/uploads/2021/10/d85aed0b2793.octet” aria-descriptionpar=”bbg” title=”d85aed0b2793″/></p>
<p style==>65I_{2}=V_{s}” source=”wp-content/uploads/2021/10/222e48f80854.octet” aria-descriptionpar=”bbh” title=”222e48f80854″/></p>
<p style==>I_{2}=frac{V_{s}}{65}” source=”wp-content/uploads/2021/10/9195aa1007f3.octet” aria-descriptionpar=”baby” title=”9195aa1007f3″/></p>
<p style=now the power dissipated through the 15 ohm resistor is

=>P=I^{2}*R” source=”wp-content/uploads/2021/10/326b56421ea2.octet” aria-descriptionpar=”bbj” title=”326b56421ea2″/></p>
<p style= =>P=V_{s}^{2}*frac{15}{4225}” source=”wp-content/uploads/2021/10/a9f904a003b9.octet” aria-descriptionpar=”bbk” title=”a9f904a003b9″/></p>
<p style= fn_jvn =>P=10.74mW” source=”wp-content/uploads/2021/10/57033fa3e51b.74mw” aria-descriptionpar=”bbl” title=”57033fa3e51b”/></p>
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