The four tires of an automobile are inflated to a gauge pressure of 1.9 105 Pa. Each tire has an area of 0.02

It’s intractable unless you assume the entire weight of the car is supported by air pressure, which is ridiculous. The rubber should be as thin as a balloon. The sidewalls of the tire actually support some of the weight (more on narrow tires).

However, if the side walls are absurdly fragile, you can use the equation P = F / A, where P is pressure, F is force, and A is area.

The total contact area is 4 * 0.028 m^2 = 0.112 m^2. The pressure is 1.9 * 10^5 Pa. Resolution:

P=F/A

P*A=F

F = (1.9 * 10^5 Pa) * (0.112 m^2)

F = 21280N

The weight of the car is 21280 Newtons.

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