Solve log2x = log53 + 1 by graphing. round to the nearest tenth.
Answer 1
3.2 Step-by-step explanation:
answer 2
3.2 Walkthrough: This is the correct answer in ed-genuity. To find the answer, first change both sides of the equation in the base change formula. You’ll end up with: When you plug these into a graphing calculator like the one provided by rd-genuity, you get 3.2 as the x-value where the two lines intersect (rounded to the nearest tenth). I hope this helps you!
answer 3
x=5 and 1/2 Walkthrough: you need to go to a graph and simplify, it’s much easier, hope this helps!
answer 4
A. (-0.8.0), (1.2.0), (2.0) Walkthrough: If you put the equation on a graphing calculator, all points given in this answer option can be found on the graph as the x-intercept.
Answer 5
B rearranges in standard form: ax² + bx + c = 0 (a≠ 0) 2x² – 3x – 2 = 0 (x – 2)(2x + 1) = 0 (set each factor to zero and solve for x ) x – 2 = 0 ⇒ x = 2 2x + 1 = 0 ⇒ x = – 0.5
Answer 6
Step-by-step explanation: 3.2
Answer 7
Walkthrough: Given: To Find: Solve each equation using graphs. Solution: See attached figure. So the values of x are -1, -6 So option B is correct. So the values of x are -1, -6
Answer 8
Steps to solve: 2x^2 + 5 = 11x ~Subtract 11x for both sides 2x^2 – 11x + 5 = 0 ~Factor (2x – 1)(x – 5) = 0 ~Solve for each factor 2x – 1 = 0 2x = 1 x = 1/2 x – 5 = 0 x = 5 Good luck!
Answer 9
x= 1.8 Walkthrough: We were given the equation; -(6)^(x-1)+5=(2/3)^(2-x) We need to determine the value of via graph. To do this, we can split the right and left sides of the equation to form the following two separate equations; y = -(6)^(x-1)+5 y = (2/3)^(2-x) Next, we plot both equations on the same graph. The solution will be the point where the equations intersect. Find the attachment below for the table; The value of x is 1.785. To the nearest tenth, ax = 1.8
Answer 10
y=-0.25x+4.07 y=4.9x-1.64 Step by step explanation: The intersection of the two graphs is the solution of the system of equations using a graphing tool see the attached figure The solution is the point, so the answer is The approximate solution of the system is