as TiO2
The ionic character of a bond deals with the difference in electronegativity between the elements. for example: NaF has more ionic character because the difference between the electronegativities for Na and F = 4 – 0.9 = 3.1
while remaining ionic, NaCl is less ionic, has less ionic character, because the difference between the electronegativities for Na and Cl = 3 – 0.9 or 2.1
Ionic bonds are characterized by an electronegativity difference of 1.7 or more. if a bond has a difference of 1.7, it is said to be 51% ionic.
TiO2 would have an electronegativity difference of 3.5 – 1.5 = 2, this would have an ionic character percentage of 63%
it’s not something you can just pull out and find out
Calculate the percentage of ionic characters
The basic equation for determining the percent ionic character of compound AB is (XA-XB)/XA (times 100%), where X is the electronegativity value of an element. The element with the highest electronegativity is chosen as element A. So for HI the electronegativity for H is 2.1 and I is 2.5. So, I is element A and H is element B: % Ionic Carbon (HI) = (2.5-2.1)/2.1 = 19.05%
ionic character
The percentage of ionic character depends on the electronegativities of the XA and XB ions according to
%CI = [ 1-exp ^ -0.25( XA-XB) ^2 ] x100