Graph the six terms of a finite sequence where a = 5 and r = 1.25. {(1,6,25),(2,7,813),(3,9,766). (4.12207),(5.15259), (6, 19.073) 20 15 10 {(1.5),(2.6,25),(3.7813).(4,9,766).(5, 12207) .(6, 15259) 15 10 ((1.-6.25), (2.-7.813).(3.-9.766).(4.-12.207).(5.-15.259)(6.-19.073) – 10-15-20-25 15 .-6.25). (6-7,813). (7.-9766), (8-12 207). 19, -15 259) (10.-19.073) 9 10 -10 – 15+ -20
Answer 1
92 = Finite sequence when a, esr=1.25 ai is the first term, r is the common ratio, then the sequence is a geonon’cal sequence, so senės au air air? ar? …. air = 5(1.25)=6.25 5(1.25)2 = 4.813 5 (1.25)3 = 9.766 S(1.25) a6 = air 5(1.25) = 15.259 Six passes are (15);R;6.25); (3,7,813)3(4,9,766); (5.12.207); (6.15.359) a3 = ara au = = a 83 a.r4 4 12.207 Os =
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