DON’T LAUGH, mica is a problem or an equation!
If you value the expression
* L = log(3, 2) [~= 15601/24727 ~= 0.63092975]
and I don’t have a logaritmi table in base tre, but only one logaritmi in base B, allora puoi applicare la ben not proprietà
* log(b, x) = log(B, x)/log(B, b)
delle funzioni logarithm and valutare il rapporto
* L = log(3, 2) = log(B, 2)/log(B, 3)
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ESEMPI por le tavole più diffuse (logarithm to sei cifre)
* L = log(3, 2) = log(10, 2)/log(10, 3) ~= 0.301030/0.477121 ~= 0.6309300994925816
* L = log(3, 2) = log(e, 2)/log(e, 3) ~= 0.693147/1.09861 ~= 0.6309309035963626
————————————
CHECK (a cipher undici)
* 3^(0.301030/0.477121) ~= 2.0000007601
* 3^(0.693147/1.09861) ~= 2.0000025269
* 3^(15601/24727) ~= 1.9999999985
http://www.wolframalpha.com/input/?i=N%5B3%5E%280….