First, find the gradient of the line AB 14–3/7–10 17/17 = 1 Since CD is perpendicular to AB, take the negative inverse of the gradient of AB to find the gradient of CD Gradient of CD = -1 to find the y-intercept using data points 12=(-1 x 5) +c 17 = c C is the y-intercept, so for question 1 the answer is 3 for the second question, just plug the values into the equation and see if you get the correct y value. the number that works is -2 for question 2 the answer is 2
x the intercept of the CD is (17, 0) The point (-2, 19) is on the CD
Answer 6
Solution: CD is perpendicular to AB and passes through point C(5, 12) The coordinates of A and B are (-10, -3) and (7, 14) Find the slope of AB From given, By substituting we get, CD is perpendicular to AB We know that, Product of the slope of AB and the slope of the line CD which is perpendicular to AB is equal to -1 Therefore, the equation of CD in slope-ordinate form at the origin is: y = mx + c — —— eqn 1 Where, m is the slope c is the y-intercept Substitute m = -1 and (x, y) = (5, 12) in the eqn 1 12 = -1(5) + cc = 12 + 5 c = 17 Replace m = -1 and c = 17 in eqn 1 y = -x + 17 —— eqn 2 The x-intercept is found by setting y equal to 0 0 = -x + 17 x = 17 So the x-intercept of CD is (17, 0) For the second part we just connect the different points and see if the equation is true: Substitute (x, y) = (-5, 24) in eq. 2 Thus, Point (-2, 19) is on CD
y = -x + 17 Walkthrough: A(-10,-3) B(7,14) C(5,12) Requires line CD perpendicular to AB passing through C. Solution: Slope of AB, m1 = (yb-ya) / (xb-xa) = (14- -3) / (7- -10) = 17/17 = 1 slope of CD, m2 = -1/m1 = -1 / 1 = -1 Line CD to C, using point slope shape y-yc = m2(x-xc) y-12 = -1 (x-5) rearrange y = -x + 5 + 12 y = -x + 17
Answer 7
White 1: (19.0) White 2: (7.-10)
It’s hard sorry I can’t you
First deviation (17.0) Option 3 is correct Second deviation (-2.19) Option 2 is correct Walkthrough: CD is perpendicular to AB C(5.12) A(-10,-3) B (7 ,14 ) CD ⊥ AB Thus, the slope of CD is the negative inverse of the slope of AB slope of CD, m=-1 (CD ⊥ AB ) Point C: (5.12) Equation of the line CD, for the abscissa: Put y=0 the abscissa: (17.0) For the second blank, we have to check each point. Option 1: (-5.24), Put x=-5 and y=24 False Option 2: (-2.19), Put x=-2 and y=19 True Option 3: (7,-10), Put x=7 and y=-10 False Option 4: (8.11), Put x=8 and y=11 False So, First white (17.0) and Second white (-2.19)
Answer 6
Solution: CD is perpendicular to AB and passes through point C(5, 12) The coordinates of A and B are (-10, -3) and (7, 14) Find the slope of AB From given, By substituting we get, CD is perpendicular to AB We know that, Product of the slope of AB and the slope of the line CD which is perpendicular to AB is equal to -1 Therefore, the equation of CD in slope-ordinate form at the origin is: y = mx + c — —— eqn 1 Where, m is the slope c is the y-intercept Substitute m = -1 and (x, y) = (5, 12) in the eqn 1 12 = -1(5) + cc = 12 + 5 c = 17 Replace m = -1 and c = 17 in eqn 1 y = -x + 17 —— eqn 2 The x-intercept is found by setting y equal to 0 0 = -x + 17 x = 17 So the x-intercept of CD is (17, 0) For the second part we just connect the different points and see if the equation is true: Substitute (x, y) = (-5, 24) in eq. 2 Thus, Point (-2, 19) is on CD
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