The answer to your question is below Explanation: Reaction C₂H₂ (g) + O₂(g) ⇒ CO₂ (g) + H₂O (g) Reactants Elements Reactants 2 C 1 2 H 2 2 O 3 This reaction is unbalanced Balanced reaction 2C₂H₂ (g ) + 5O₂(g) ⇒ 4CO₂ (g) + 2H₂O (g) Reactants Elements Reactants 4 C 4 4 H 4 10 O 10 The reaction is now balanced a) Calculate the molecular mass of acetylene and water Acetylene = (12 x 2 ) + (2) = 26 g Water = (1 x 2) + (1 x 16) = 18 g 2(26) g Acetylene 2(18) g Water 113 g Acetylene xx = (113 x (2) x 18)) / 2(26) x = 4068 / 52 x = 78. 2 g of water b) 2 moles of acetylene 4 moles of carbon dioxide cx moles of acetylene 1.10 moles of dioxide of carbon x = ( 1.10 x 2) / 4 x = 0.55 moles of acetylene
The answer to your question is below Explanation: Reaction C₂H₂ (g) + O₂(g) ⇒ CO₂ (g) + H₂O (g) Reactants Elements Reactants 2 C 1 2 H 2 2 O 3 This reaction is unbalanced Balanced reaction 2C₂H₂ (g ) + 5O₂(g) ⇒ 4CO₂ (g) + 2H₂O (g) Reactants Elements Reactants 4 C 4 4 H 4 10 O 10 The reaction is now balanced a) Calculate the molecular mass of acetylene and water Acetylene = (12 x 2 ) + (2) = 26 g Water = (1 x 2) + (1 x 16) = 18 g 2(26) g Acetylene 2(18) g Water 113 g Acetylene xx = (113 x (2) x 18)) / 2(26) x = 4068 / 52 x = 78. 2 g of water b) 2 moles of acetylene 4 moles of carbon dioxide cx moles of acetylene 1.10 moles of dioxide of carbon x = ( 1.10 x 2) / 4 x = 0.55 moles of acetylene
a) 78.19 grams of H2O b) 14.3 grams of acetylene Explanation: Step 1: Data given Molar mass of acetylene = 26.04 g/mol Molar mass of H2O = 18.02 g/mol Step 2: The balanced equation 2C2H2 + 5O2 → 4CO2 + 2H2O Step 3: A. How many grams of water can be formed if 113 g of acetylene are burned? Calculate moles of acetylene: Moles = mass / molar mass Moles = 113.0 grams / 26.04 g/mol Moles = 4.339 moles calculate moles of H2O For 2 moles of acetylene we need 5 moles of O2 to produce 4 moles of CO2 and 2 moles of H2O For 4.339 moles of acetylene we will have 4.339 moles H2O Calculate the mass of H2O Mass H2O = 4.339 moles * 18.02 g/mol Mass H2O = 78.19 grams H2O b. How many grams of acetylene react if 1.10 moles of CO2 are produced? For 2 moles of acetylene, you need 5 moles of O2 to produce 4 moles of CO2 and 2 moles of H2O For 1.10 moles of CO2, you need 1.10/2 = 0.55 moles of acetylene Mass of acetylene = 0.55 moles * 26.04 g/mol Mass of acetylene = 14.3 grams of acetylene
a) 78.19 grams of H2O b) 14.3 grams of acetylene Explanation: Step 1: Data given Molar mass of acetylene = 26.04 g/mol Molar mass of H2O = 18.02 g/mol Step 2: The balanced equation 2C2H2 + 5O2 → 4CO2 + 2H2O Step 3: A. How many grams of water can be formed if 113 g of acetylene are burned? Calculate moles of acetylene: Moles = mass / molar mass Moles = 113.0 grams / 26.04 g/mol Moles = 4.339 moles calculate moles of H2O For 2 moles of acetylene we need 5 moles of O2 to produce 4 moles of CO2 and 2 moles of H2O For 4.339 moles of acetylene we will have 4.339 moles H2O Calculate the mass of H2O Mass H2O = 4.339 moles * 18.02 g/mol Mass H2O = 78.19 grams H2O b. How many grams of acetylene react if 1.10 moles of CO2 are produced? For 2 moles of acetylene, you need 5 moles of O2 to produce 4 moles of CO2 and 2 moles of H2O For 1.10 moles of CO2, you need 1.10/2 = 0.55 moles of acetylene Mass of acetylene = 0.55 moles * 26.04 g/mol Mass of acetylene = 14.3 grams of acetylene
Acetylene C2H2 gas is burned to form carbon dioxide and water when used in the oxyacetylene welding torch. Balance the reaction and answer the following questions. C2H2(g)+O2(g) —> CO2(g)+H2O(g) a. How many grams of water can be formed if 113 g of acetylene is burned? B How many grams of acetylene react if 1.10 moles of CO2 are produced? PLEASE SUBMIT YOUR WORK! Explanation: Acetylene C2H2 gas is burned to form carbon dioxide and water when used in the oxyacetylene welding torch. Balance the reaction and answer the following questions. C2H2(g)+O2(g) —> CO2(g)+H2O(g) a. How many grams of water can be formed if 113 g of acetylene is burned? B How many grams of acetylene react if 1.10 moles of CO2 are produced? PLEASE SUBMIT YOUR WORK!
Answer 6
C2H2 + 3O2 -> 2H2O + 2CO2 Using the molar ratios we get that we get 8.68 moles of water for 4.34 moles, so since the molar mass of water is 18 grams per mole we multiply 18 * 8.68 = about 156.24 grams.
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