Can you show me how you got the answer?
The first thing you need to do is find the mass of a 0.0480 molal solution if you assume you have 1 kg of solvent (that would mean you have 0.0480 mol of solute, LiF).
Once you assume 1 kg of solvent, you find the mass of 0.0480 mol of LiF and add it to the mass of solvent to get the mass of the solution.
Now you can divide the mass of the solution by the density of the solution to get the volume of solution you have.
After determining the volume of the solution, you can calculate the molarity of the solution because you already know the number of moles in the solution (0.0480 mol)
that’s to say:
1.) assume 1 kg of solvent
2.) Mass of 0.0480 mol of LiF = (# of moles) x (molar mass) = 0.0480 mol x (25.939g/mol) = 1.245g (0.001245kg)
3.) add the mass of solvent and solute to get the mass of solution = 0.001245 kg + 1 kg = 1.001245 kg
4.) divide by the density of the solution to get the volume of the solution = (1001.245g) x (1mL/1.10g) = 910.22mL (0.9102L)
5.) calculate molar concentration = (moles of solute) / (liters of solution) = (0.0480mol) / (0.9102L) = 0.0527M
answer: 0.0527M
Take a hypothetical sample of exactly 1000 L (1000 mL) of the solution.
(1000ml) × (1.10g/ml) = 1100g
“0.0480 m” means 0.0480 mol LiF in 1000 kg of solvent.
(0.0480 mol LiF/kg) x (25.9394 g LiF/mol) = 1.245 g LiF in 1.000 kg solvent
(1100 g) x (1.245 g) / (1.245 g + 1000 g) = 1.3677 g LiF in 1100 g solution
(1.3677 g LiF) / (25.9394 g LiF/mol) = 0.0527 mol LiF
So there are 0.0527 mol LiF in each liter of solution, so the molarity is 0.0527 M LiF.