One side of the tank contains an ideal gas at 927 degrees Celsius. The other side is evacuated and has a volume twice the size of the part containing the gas. The separators are now removed and the gas expands to fill the entire tank. Heat is then applied to the gas until the pressure is equal to the initial pressure. Determine the final temperature of the gas. Please help me I don’t know what to do =/
Answer 1
Ti = 927 degrees. C=1200K
Vf = 3*Vi
Pi = P
Pf = P
Using the ideal gas equation,
PiVi/Ti = PfVf/Tf, Pi = Pf
Vf/Ti = Vf/Tf
Tf = Ti*(Vf/Vi)
Tf = 1200*(3)
Tf = 3600 K = 3327 degrees. VS
answer 2
I don’t understand if you know 2nd grade equations so I’m giving you a much less complicated answer, just divide 1512 into factors: 1512 = 2x2x2x3x3x3x7 now you should multiply some of them and something else like thanks to getting the sum seventy 8 social gathering; try 2x2x2x3=24 and the last 3x3x7=sixty 3 and you don’t get seventy 8 more after some tries you will find 2x2x3x3=36 and the last 2x3x7=40 2 which has the sum seventy 8 so the nrs are 40 2 and 36 this problem is unquestionably solved with 2d degree equations » allow the first nr to be x and the 2d to be seventy 8-xu have x*(seventy 8-x)=1512 78x -x^2-1512=0 or x^2 – 78x+ 1512=0. then you continue with the wording, if you understand