Which of the following would be the lowest in cephalization? a. arthropods b. mammals C. mollusks D. cnidarians
The answer is D. Cnidarians
The correct answer is: D) Cnidaria. Cephalization is a process that describes the occurrence of a definite head possessing a well-developed mind, which controls the entire body of the organism. Vertebrates such as mammals are basically the most heady organisms as they include a highly developed head with a nervous system. Among invertebrates, some cephalic organisms include insects, spiders, mites (which come below arthropods). Cnidarians like sea anemones, jellyfish have weaker cephalization because they only contain a fundamental nervous system, but they are headless.
the answer is A. hope you bought a very good review
The answer is B. Cnidarians
They are cnidarians, the cnidarians of the phylum all have diploblastic animals and therefore exist in polyp type (stationary type) or medusa type (free-swimming type). Diploblastic animals have only two layers of cells, they have a mouth, but the physical division of head and trunk does not exist in this phylum. Hydra is a traditional example of cnidarians. While they have an anterior and posterior finish but no clearly demarcated cephalic construct and hence they would be the lowest in cephalization
My biggest answer might be A) Cnidarians
Redone is the least I believe
when organisms tend to cluster all of their major organs near the entrance to their body.
Which biotic factor would limit the antelope population in the african savanna?
What biotic problem would constrain antelope dwellers in the African savannah? Answer 1 Maybe it's the Lions, if that's an alternative then yes Answer 2 Any predator of the inhabitants/species of antelope in that space, or any human air pollution can also have an effect on him. Hope this helps. Answer 3 The correct answer is B) Leo . In the African savannah, several restaurant chains operate. Any food chain is made up of totally different producers and buyers. In a given query, antelopes are herbivores. They are the first buyers and eat inexperienced vegetation (producers). Whereas lions are carnivorous. They are predators that kill antelopes and eat them. Thereafter, the lion will compel the antelope dwellers in the African savanna. atmosphere, or an effect on the inhabitants of the ecosystem. A later biotic problem that will limit antelope dwellers might be lions. Answer 6 Hope this helps
radish flowers may be red, purple, or white. a cross between a red-flowered plant and a white-flowered plant yields all-purple offspring.
Answer 3 There is incomplete dominance when the heterozygous phenotype is intermediate between the homozygous dominant and homozygous recessive phenotypes. In radish flowers, purple is intermediate to white and red flowers. Thus, the purple color is characteristic of heterozygous phenotypes. When dominant red flowers are crossed with recessive white flowers, all offspring will be heterozygous and intermediate in color – purple. Answer 2C: Violet and long Explanation: Let R be the color of the flower. The RR genotype will give a red flower, Rr will be purple (incomplete dominance) and rr will be white. Let L be the length of the radish. LL and Ll will result in long radishes because the long radish allele is dominant over the oval radish allele. Each genotype will produce oval-shaped radishes. Crossing RRLL with rrll: All offspring will have the RrLl genotype (see attached image for Punnet square result). Phenotypically, they will appear with a purple bloom and long radishes. The correct answer is C. Answer 16:3:3:2:1:1 Explanation:
The illustration below represents what stage of meiosis?
The illustration below represents which stage of meiosis? a. prophase ib. anaphase iic. identification of telophase. iReply 1B metaphase. Anaphase 2 due to sister chromatids move to totally different poles. Answer 2B. Anaphase II, because the chromosomes seem to have crossed and that means it's anaphase II. However, this could be metaphase I as they have not separated and this is when the chromosomes cross over. So it could be Anapase II or Metaphase I. Answer 31,2,4,5,6,3 Clarification: Meiosis involves two rounds of cell division to create 4 haploid cells, therefore we all know 3 should be the final step. Meiosis begins with a diploid cell after DNA replication. Therefore, stage 1 is the primary one. Homologous chromosomes line up (as proven in step 2). Then the chromosomes are pulled apart to reverse cell poles (4) and two new cells begin to form, before cell division (5). Then the chromosomes of these two cells line up in the center of the cells (6) and the sister chromatids are pulled apart to create 4 haploid cells (3)Answer 4Do you have the picture?Answer 5It could definitely be prophase due to a doubling chromosome. but without the picture it's really hard to tell
Which of the following describes how the winter season affects organisms in the tundra biome?
Which of the following statements describes how the winter season affects organisms in the tundra biome? a. cold temperatures kill many crops. B crops enlarge their leaves to absorb daylight. vs. the predator/prey ratio will increase. D. animals not adapted to cold migrate to warmer areas Answer 1 The correct answer to this question is option D. Animals not adapted to cold migrate to warmer areas. Clarification: Let's just affirm this particularity by testing the birds, they are a great example of this because they have a great advantage through different organisms, they will fly, and by doing this, it is easy for them to go to another biome. If a selected species of chicken wants a scorching climate to enjoy its meals, there is no need for a cold place, so the chicken will likely seek out a warmer place where there is enough food to survive. if the organism is not adapted to the tundra, it may migrate or it may die from extremely cold weather around -30 degrees Fahrenheit. result of assuming that cold temperatures kill many crops, so if they are going to die, why did they choose this place to stay? Choice B will not Read more