Data Interpretation: Hardy-Weinberg Equation Part A Can you use the Hardy-Weinberg equation to answer questions about the hypothetical cat population? A hypothetical population of 500 cats has two alleles, T and t, for a gene that codes for tail length. (It is completely dominant for t.) The table below shows the phenotype of cats with each possible genotype, as well as the number of individuals in the population with each genotype. Drag the numbers on the left into the appropriate spaces on the right to answer these questions. Responses can be used once, multiple times, or not at all. Reset help Suppose this population is in Hardy-Weinberg equilibrium. Recall that the Hardy-Weinberg equation is p2+2pq+q2-1 0.16 0.36 0.40 0.48 0.60 0.84 80 180 420 1. How common are cats with long tail in the population? 2. How common are short-tailed cats in the population? Phenotype Genotype Number of individuals with long tailTT long tail short tail 180 240 80 Tt 3. What is the frequency of homozygous dominant cats in the population? 4. How common is Tallele in the gene pool of this population? 5. How common is talele in the gene pool of this population?
Answer 1
1. The frequency of long-tailed cats in the population
He is
0.84
The total number of long-tailed cats is 180 + 240 = 420, total number of cats
500,
The frequency is therefore 420/500 = 0.84
2. The frequency of short-tailed cats in the population
He is
0.16
q2 = 80/500 = 0.16
3. The frequency of homozygous dominant cats in
the population is
0.36
p2 = 180/500 = 0.36
4. The frequency of the T allele in this gene pool
the population is
0.60
The total number of T alleles in the population is 180 + 240/2 = 300,
The total number of cats is 500,
So the frequency of the T allele is 300/500 = 0.60
5. The frequency of the t allele in this gene pool
the population is
0.40
The total number of t alleles in the population is 80 + 240/2 = 200,
The total number of cats is 500,
So the frequency of the t allele is 200/500 = 0.40