Balanced net ionic equation
answer 2
Hi Ko
answer 3
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A. H⁺I + KOH = H2O + KI H⁺Iˉ + K⁺OHˉ = H⁺OHˉ + K⁺Iˉ without net ionic reaction B. Na2SO4 + CaI2 = CaSO4 + 2 NaI 2Na⁺SO4²ˉ+Ca²⁺[2Iˉ] =Ca²⁺SO4²ˉ+2Na⁺Iˉ do the same for the others
Answer 1
general equation: HI(aq) + KOH(aq) —> KI(aq) + H2O(l)
full ionic: H+(aq) + I-(aq) + K+(aq) + OH-(aq) —> K+(aq) + I-(aq) + H2O(l)
ionic liquid: H+(aq) + OH-(aq) —> H2O(l)