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7 is the correct answer.
the principal quantum number, n, indicates the total energy of an orbital.
Hey bro, this sounds like a McGraw-Hill connection question. What do you notice, I just answered on my account. 6s, 6d, 6d, 6f, 6g, 6h are all obtained THEORETICALLY. check them all out! a little effective know-how; the style of the orbitals in the substages will progress according to the outlier numbers (one million, 3, 5, 7, 9, 11, . . .). So start with 6s=one million, 6p=3, and kill the rest as well. (Google a large quantum size chart and browse the process photos to find anything up to n=7 if you go for the visual representation.)
The energy of an orbital and the total size of an orbital
total size of an orbital
the energy of an orbital
Source(s): MC and page 315 of the 3rd ed Molecular Approach
the correct answer is 1 and 7
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