Physics: A child bounces in a harness suspended from a door frame by three elastic bands question?

(a) If each rubber band stretches 0.280 m while supporting a 5.95 kg child, what is the force constant for each rubber band?

Answer 1

(a) Assuming equilibrium,
2 * F = m*g = 5.95 kg * 9.8 m/s² = 58.3 N
F=29.2N=kx=k*0.280m
k = 104 N/m

(b) T = 2π√(m/k) = 2π√(5.95kg / 104N/m) = 1.50s

(c) Vmax. = A*ω = A*2π/T
V max. = 0.280m * 2π / 1.50s = 1.17m/s

I hope this helps you!

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