How many moles of argon gas contain 7.52 x 10^22 Ar atoms?

total particles = moles x Avogadro’s constant

avogadro’s constant = 6.02 x 10^22 particles

then,

7.52 x 10^22 = moles. 6.02×10^22

moles = 7.52 x 10^22 divided by 6.02 x 10^22
moles = 1.24916943521 moles

7.52 X 10^22 Ar atoms / 6.02 X10^23 atoms per mol = 0.1249 mol

1 mole of atoms = 6.02 x 10^23 atoms
so, moles of argon gas = (7.52 x 10^22)/(6.02 x 10^23)
=0.125 mol
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PRINCIPLE: 1 mol of ANY GAS COMPOUND or ELEMENT contains 6.02*10^23 atoms at AMBIENT TEMPERATURE AND PRESSURE.

Therefore, 1 mol of argon contains 6.02*10^23 atoms
Number of moles = 7.52 x 10^22/6.02*10^23 = 0.125 mol of argon at ambient temperature and pressure.

1 mol contains 6.022 x10^23, so just divide 7.52 . . . so the atoms cancel out and leave you with moles of Ar

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6.023 × 10^23 atoms are present in = 1 mol of argon
1 atom is present in =1/6.023×10^23 mol of argon
So
7.52×10^22 are present in =1×7.52×10^22/6.023×10^23
so the answer is = 0.12485 mol contains 7.52 × 10^22 atoms