**Answer 1**

total particles = moles x Avogadro’s constant

avogadro’s constant = 6.02 x 10^22 particles

then,

7.52 x 10^22 = moles. 6.02×10^22

moles = 7.52 x 10^22 divided by 6.02 x 10^22

moles = 1.24916943521 moles

**answer 2**

7.52 X 10^22 Ar atoms / 6.02 X10^23 atoms per mol = 0.1249 mol

**answer 3**

1 mole of atoms = 6.02 x 10^23 atoms

so, moles of argon gas = (7.52 x 10^22)/(6.02 x 10^23)

=0.125 mol

ok hope i helped!! =)

All my wishes!!

**answer 4**

PRINCIPLE: 1 mol of ANY GAS COMPOUND or ELEMENT contains 6.02*10^23 atoms at AMBIENT TEMPERATURE AND PRESSURE.

Therefore, 1 mol of argon contains 6.02*10^23 atoms

Number of moles = 7.52 x 10^22/6.02*10^23 = 0.125 mol of argon at ambient temperature and pressure.

**Answer 5**

1 mol contains 6.022 x10^23, so just divide 7.52 . . . so the atoms cancel out and leave you with moles of Ar

**Answer 6**

Removes blemishes, warts and skin blemishes safely and permanently

**Answer 7**

6.023 × 10^23 atoms are present in = 1 mol of argon

1 atom is present in =1/6.023×10^23 mol of argon

So

7.52×10^22 are present in =1×7.52×10^22/6.023×10^23

so the answer is = 0.12485 mol contains 7.52 × 10^22 atoms

**Answer 8**

o.125 moles of air

**Answer 9**

why don’t you use a calculator