Answer 2C) 10(a + 10) = 12 2 Step by step explanation: on the edgeAnswer 3Tangent²=(Any secant segment)(External secant segment) 2. Any secant segment is: AD=a+12 3. O exterior the segment secant is: BD=10 4. The tangent segment is: DE=12 5. So you have: DE²=ADxBD 12²=(a+10)10 10(a+10)=12² 6. So the answer is the third option : 10(a+10)=12²Answer 6c.) 10(a+10)=12^2 Step by step explanation: answer on the edge 2020, I just did the test, I hope it helped!!! Answer 8c’est sur le bord Walkthrough: d on edgeAnswer 4th answer is the last option: x(2x+4)=(x+2)2 WalkthroughAnswer 7is D on edge Walkthrough:Answer 10 The secant theorem e of the tangent states: If a tangent segment and a secant segment are drawn on a circle from an outer point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its outer secant segment. In the given figure DE is tangent and AD is the secant By applying the theorem we have: BD.AB=DE^{2} Substituting the values of the figure 10(a+10)=12^{2} Answer 5x( 2x+ 4) = (x+2)^2Answer 1C) 10(a+10) = 12 2Answer 6c.) 10(a+10)=12^2 Walkthrough: answer within 2020, just passed the test hope this helps!!!Answer 9Solution: The secant and tangent theorem states that the point where the secant and the tangent meet, then the square of the length of the tangent is equal to the product of the length of two segments. In the figure below, DE is the tangent and DB is the secant length. Whereas DA is the length of the segment which is equal to the point of intersection of the tangent and the secant and the secant and the circle. DE²= DA × DB →12²=10 × (a+10) Option (C) is the correct description. the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its exterior secant segment. In the given figure DE is tangent and AD is the secant By applying the Theorem we have: BD.AB=DE^{2} Substituting the values of the figure 10(a+10)=12^{2}