Part A Give the systematic name of the compound NaNO3- Spell the full name of the compound. See advice available) Submit Part B Give the systematic name of the compound Mn2(SO4)3- Spell the full name of the compound. ► View available suggestions Submit a game Enter the formula for the compound beryllium oxide Express your answer as a chemical formula. See available tips) ΑΣΦ? Submit Part D Enter the formula for the lead(ll) phosphate compound. Express your answer as a chemical formula
Answer 1
Sodium nitrate is an example of a ternary ionic compound. A
the ternary ionic compound contains two or more elements. On the inside
in this case, there are 3 (Na, Na and O).
The naming system for ternary ionic compounds is the same as for
binary ionic compounds.
Let us name the participating ions:
Na+
No. 3-
NO3- is the formula for the polyatomic ion (two or more elements
united by sharing a common burden; they act as a unit when
they combine with other elements) nitrate.
We swapped sodium and nitrate fillers. Swap
they give us the formula
NaNO3
To name this formula, just combine the name of the cation and the anion
together. In this case, it is sodium
nitrate.
2.Mn2(SO4)3 is a ternary
ionic compounds. The systematic name based on:
1. Charge of positive ions is = 3+
2. Sulphate load = 2-
Ternary compounds are named by listing the cation first,
followed by the anion.
The positive and negative charges must balance each other. The compound name is
Manganese(II) sulfate.
3. Barium oxide is an ionic
compounds Looking at the periodic table, oxygen is in the group
6 or 16 and will therefore have an oxidation number of -2, while
barium is in group 2 and will have an oxidation number of
+2.
So a molecule of barium will oxidize a molecule of oxygen
so there is no charge on barium oxide, it is a neutral
molecule and a of single BaO
Formula
barium oxide = BaO
Ba2++O2-=
Good.
4. Formula=
Pb3(PO4)2
The given Roman numeral (ll) here signifies the lead (Pb) present in
+ 2 oxidation state = pb2+ Phosphates its chemical formula is PO4
3- has charge -3 . Thus, we can use the crossover method in which the
loads will pass through several
Pb.PO4
2.3
Multiple 2 per po4 and 3 per Pb this multiple will enter
he is subscribed to it.
The formula will be
Pb3(PO4)2
To balance them, we need 3 lead(II) ions and 2 phosphate ions.
ions so that their charge is 6+ and 6-, respectively.
Therefore, the formula of lead(II) phosphate is
Pb3(PO4)2