I don’t know what it takes to find and I’m wrong. I am currently trying to solve for thermal power.
Answer 1
The maximum possible efficiency, i.e. the efficiency of a Carnot engine, is given by the ratio of the absolute temperatures of the hot and cold tank.
η_max = 1 – (T_c/T_h)
For this engine:
η_max = 1 – [ (20 +273)K/(600 + 273)K ] = 0.66 = 66%
The actual efficiency of the motor is 30%, i.e.
η = 0.3 ∙ 0.664 = 0.20 = 20%
On the other hand, thermal efficiency is defined as the ratio between the work done and the amount of heat absorbed by the hot reservoir:
η = W/Q_h
Thus, the heat demanded from the hot reservoir is:
Q_h = W/η = 1000J / 0.20 = 5000J
answer 2
one million.- there is no longer such an element as a hundred% conversion, often there is a loss of potential due to the transformation from one style of potential to another, relatively it is declared as Entropy and is absorbed by the ability of the universe. 2.- using the way you interpret potential gadgets; often inside the refrigeration cycle, it is seen that the heat evacuated in an area of the appliance (air conditioning unit) of the refrigerated room, is “heat rejected in the open air”, the amount of this heat rejected is that of the heat removed from the part plus the heat produced in the electrical aspects of the unit plus any additional losses produced as friction in the reference. tubes etc…etc. In theory, you can rate it relatively twice the amount of heat you removed from the room. All the different questions can, in simple terms, be answered once you have defined the gadgets (ft-lbs, btu/hr, joules, watts, etc. etc. etc.) and declared the capacity of the AC unit or heat pump.