Please help me! A ray of light in the air is refracted when it enters the glass and undergoes total internal reflection from the air at the bottom surface of the glass; and is then refracted again as it rises through the glass in the air. The upper and lower glazed surfaces are parallel to each other. What possible angles of incidence, 0, will allow this to happen? 3. 01 TIR air glass)
Answer 1
In the ray, the light from the air is refracted on entering the glass and undergoes total internal reflection at the glass-air interface at the bottom: r_1: angle of incidence n_ar: index of refraction of the hair = 1 n_glass : glass refractive index = 1 . 52 For total internal reflection n_glass sin r_1 = n_air (1.52) sin r_1 = 1 sin r_1 = 0.658 r_1 = 41.15 degrees at the air-glass interface. rn using Snell’s law n_ar sin theta_1 = n glass sin r_1 1 sin theta = 1 = (1.52)sin 41.15 theta_1 = 90