Find the slope of each line. 1) 2) Find the slope of the line passing through each pair of points. 3) (1, 12), (-18, 12) 4) (-6, 17), (-18, 2) 5) (-16, -5), (-1, -12) 6) (3 , 11), (4,3) Write the slope-intercept form of the equation for each line given the information. 1) 3 2) Slope ordered at the origin = -2 2 NI I 3) y – 5= 3(x – 1) 4) Given the points: (1, 1) and (0.5) 5) Given the points: (4 .-4) and (2, -1)
@ Find the slope of each line. ។ 7 Data 3 From the graph. take a unit of length and the dots represent (4,0) and (+,-3). Dare the points ₂ then the slope is given by mislepe) – You can let (x, y) and 4-) slope of the given line = 3/5 write the 3 ។ from the line goes through (-3,1) and (4,-1) the slope of the slope = २ -7 -3-4 – 2 / 2 slope of the given time =-2/ (3 Given: The colon stop sleeping passing through points (49) and (hm, Hz) is ‘m Tey, given points are = C.,k),(-18,12) 7, slope = 12-12 1-446 ) 1 slope of the line passing through the point is zero.
the given points (-6.17), (-19.2) are the slope of the line passing through the points is given by slope = 17-2 -6-618) 12 +9 -7 slope = -5-62 ) – 12 – 16+1 5 slepe a slope sta of the thin passes passing through given points is sta ③ Gueye-(-16, 5), (1, 2) are the points through which the slope of the line passing through the points is given. -16-(-1) the slope of the line is -7/15 @ Givene – (3.11), (2.3) are the points. the slope of the Fine passing through the points is given by. the slope of the line is “_s”. @ write the intercept frame of the slope of each line given the information. Imp The equation of the straight line at the origin of the slope fam is Y= mxtc. m=line slope c = “-intercept line. 1.3 .8 3-4
– 3 – Daivan From the painting. g. the intercept step is given by the line passing through m = slope = 400-6-3) at (40) and (63). – – – – 름 will mate y =2x-3 44=34-12 y = 31 3 2 slope: 2 x intercept 2-2 3x 2 2y=3x-4 34-2y = 4. 3 45=3(+ 1 ) 9-5=31-3 y-3x=2. 4. Given points (II) and (015) & Gr Bid time passing through too many points. (1,4) and (M292) is given by (4-4)-CL 2004)
(4-1) = (5-1) (n-1) y-1 -461) y-1 – A4 Lenty- { points (4,-4) and (2,1) same as problems above. (4+4) – Chry) Cm4) Yeu -24-8 = 3×112 3×124 = 4.